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22x^2-37x+6=0
a = 22; b = -37; c = +6;
Δ = b2-4ac
Δ = -372-4·22·6
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-29}{2*22}=\frac{8}{44} =2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+29}{2*22}=\frac{66}{44} =1+1/2 $
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